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Math

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gufran.merchant




PostSubject: Math Wed Mar 17, 2010 12:42 pm

This year a question on mean value theorem and conics will come for 10 marks also a question from Boolean algebra and inverse will come for 10 marks
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anjanavr47
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PostSubject: Re: Math Thu Mar 18, 2010 7:46 pm

isn't that the pattern mentioned in the specimen paper Question
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niharika_505
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PostSubject: Re: Math Tue Jun 01, 2010 8:06 pm

can ny1 plz solve dis question:



[b](sin^4x)*(cos^4x)
plz plz plz solve it
thnk u
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PostSubject: Re: Math Tue Jun 01, 2010 9:21 pm

s0ry but can u mention the question..?! Very Happy
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PostSubject: Re: Math Wed Jun 02, 2010 1:38 am

i jus wrote.............ill write it again


(sin^4x)*(cos^4x)
sin to the power of 4x(4 ex) multiplied by cos to the power of 4x(4 ex)
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PostSubject: Re: Math Wed Jun 02, 2010 2:56 pm

sorry but u knw, the sine format is like "sin" followed by a variable like "sin x" ... what is that "x" here..? Your question is immersed in ambiguity.!
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abhas
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PostSubject: Re: Math Wed Jun 02, 2010 4:27 pm

I think she wants to say



may be the question is to simplify above expression using standard trigno formulas
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PostSubject: Re: Math Wed Jun 02, 2010 5:39 pm

ya abhas thts rite..........thts my question!!!!!! Smile
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PostSubject: Re: Math Wed Jun 02, 2010 10:36 pm

yea yea..i thought same.. but i wanted the "question" ..!! to integrate or differentiate...or simplify..like that...
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PostSubject: Re: Math Wed Jun 02, 2010 11:28 pm

u may use

2sin^2 x = 1 − cos(2x)
and cos(2α) = cos2α − sin2α

to simplify the expression to some extent....but ur question seems to b incomplete as in ISc OR icse usually it is asked to prove some expression equal to other...procedure of simplification will vary according to required simplified expression
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anjanavr47
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PostSubject: Re: Math Thu Jun 03, 2010 12:25 am

were did u get this question?
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niharika_505
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PostSubject: Re: Math Thu Jun 03, 2010 2:10 am

its from my math isc book................nd no no no u dont hv to prove u jus hv 2 solve it
thnx 4 da pains
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abhas
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PostSubject: Re: Math Thu Jun 03, 2010 2:27 am

you mean we have to solve it for x

then the question must be like this (sin^4x)*(cos^4x)=something

can u please tell the answer.Also tell the book which u r following.Is it M.L. Aggrawal???
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PostSubject: Re: Math Thu Jun 03, 2010 6:30 pm

Yes. Abhas is right. There must be some RHS to solve. Only an equation can be solved not an expression. This is currently an expression. What is the RHS part?
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anjanavr47
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PostSubject: Re: Math Fri Jun 04, 2010 12:40 am

do u just need to simplify it?
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Complete IIT AIEEE ICSE ISC PMT help forum :: ISC :: ISC 2010 [Class xii] :: Maths-